delta:= mat((0,0,0,0,0,0),(1,0,0,0,0,0),(0,0,0,0,0,0),(0,0,a,0,0,0),(0,b,1,0,0,0),(0,0,0 ,0,a - 1,0))$ shortformdelta:={1, ss, 0, 0, ss, a, ss, b, 1, ss, 0, 0}$ phase 1 de la resolution des equations$ on resout l'equation {{0,1},0} qui est maintenant AA:= - d(0,2)$ Unknown: d(0,2) Unknown: d(0,2) bonne inconnue W:=d(0,2)$ sa valeur doit etre WW:=0$ on resout l'equation {{0,1},1} qui est maintenant AA:= - d(1,2)$ Unknown: d(1,2) Unknown: d(1,2) bonne inconnue W:=d(1,2)$ sa valeur doit etre WW:=0$ on resout l'equation {{0,1},2} qui est maintenant AA:= - d(2,2) + d(1,1) + d(0, 0)$ Unknowns: {d(2,2),d(1,1),d(0,0)} Unknowns: {d(2,2),d(1,1),d(0,0)} bonne inconnue W:=d(2,2)$ sa valeur doit etre WW:=d(1,1) + d(0,0)$ on resout l'equation {{0,1},3} qui est maintenant AA:= - d(3,2)$ Unknown: d(3,2) Unknown: d(3,2) bonne inconnue W:=d(3,2)$ sa valeur doit etre WW:=0$ on resout l'equation {{0,1},4} qui est maintenant AA:= - d(4,2) + d(3,1)*a - d( 2,0)$ Unknowns: {d(4,2),d(3,1),d(2,0),a} Unknowns: {d(4,2),d(3,1),d(2,0),a} bonne inconnue W:=d(4,2)$ sa valeur doit etre WW:=d(3,1)*a - d(2,0)$ on resout l'equation {{0,1},5} qui est maintenant AA:= - d(5,2) + d(3,1) - d(3, 0) + d(2,1)*b$ Unknowns: {d(5,2),d(3,1),d(3,0),d(2,1),b} Unknowns: {d(5,2),d(3,1),d(3,0),d(2,1),b} bonne inconnue W:=d(5,2)$ sa valeur doit etre WW:=d(3,1) - d(3,0) + d(2,1)*b$ on resout l'equation {{0,1},6} qui est maintenant AA:= - d(6,2) + d(5,1)*a - d( 5,1) - d(4,0)$ Unknowns: {d(6,2),d(5,1),d(4,0),a} Unknowns: {d(6,2),d(5,1),d(4,0),a} bonne inconnue W:=d(6,2)$ sa valeur doit etre WW:=d(5,1)*a - d(5,1) - d(4,0)$ on resout l'equation {{0,2},0} qui est maintenant AA:= - d(0,5)*b$ Unknowns: {d(0,5),b} Unknowns: {d(0,5),b} pas de selection possible de variable a coefficient independant des xi dans - d (0,5)*b on resout l'equation {{0,2},1} qui est maintenant AA:= - d(1,5)*b$ Unknowns: {d(1,5),b} Unknowns: {d(1,5),b} pas de selection possible de variable a coefficient independant des xi dans - d (1,5)*b on resout l'equation {{0,2},2} qui est maintenant AA:= - d(2,5)*b$ Unknowns: {d(2,5),b} Unknowns: {d(2,5),b} pas de selection possible de variable a coefficient independant des xi dans - d (2,5)*b on resout l'equation {{0,2},3} qui est maintenant AA:= - d(3,5)*b$ Unknowns: {d(3,5),b} Unknowns: {d(3,5),b} pas de selection possible de variable a coefficient independant des xi dans - d (3,5)*b on resout l'equation {{0,2},4} qui est maintenant AA:= - d(4,5)*b + d(1,0)$ Unknowns: {d(4,5),d(1,0),b} Unknowns: {d(4,5),d(1,0),b} bonne inconnue W:=d(1,0)$ sa valeur doit etre WW:=d(4,5)*b$ on resout l'equation {{0,2},5} qui est maintenant AA:=b*( - d(5,5) + d(1,1) + 2 *d(0,0))$ Unknowns: {d(5,5),d(1,1),d(0,0),b} Unknowns: {d(5,5),d(1,1),d(0,0),b} pas de selection possible de variable a coefficient independant des xi dans b*( - d(5,5) + d(1,1) + 2*d(0,0)) on resout l'equation {{0,2},6} qui est maintenant AA:= - d(6,5)*b + d(3,1)*a - d(3,1) - d(3,0)*a + 2*d(3,0) + d(2,1)*a*b - d(2,1)*b$ Unknowns: {d(6,5),d(3,1),d(3,0),d(2,1),a,b} Unknowns: {d(6,5),d(3,1),d(3,0),d(2,1),a,b} pas de selection possible de variable a coefficient independant des xi dans - d (6,5)*b + d(3,1)*a - d(3,1) - d(3,0)*a + 2*d(3,0) + d(2,1)*a*b - d(2,1)*b on resout l'equation {{0,3},0} qui est maintenant AA:= - (d(0,5) + d(0,4)*a)$ Unknowns: {d(0,5),d(0,4),a} Unknowns: {d(0,5),d(0,4),a} bonne inconnue W:=d(0,5)$ sa valeur doit etre WW:= - d(0,4)*a$ on resout l'equation {{0,3},1} qui est maintenant AA:= - (d(1,5) + d(1,4)*a)$ Unknowns: {d(1,5),d(1,4),a} Unknowns: {d(1,5),d(1,4),a} bonne inconnue W:=d(1,5)$ sa valeur doit etre WW:= - d(1,4)*a$ on resout l'equation {{0,3},2} qui est maintenant AA:= - d(2,5) - d(2,4)*a + d( 1,3)$ Unknowns: {d(2,5),d(2,4),d(1,3),a} Unknowns: {d(2,5),d(2,4),d(1,3),a} bonne inconnue W:=d(2,5)$ sa valeur doit etre WW:= - d(2,4)*a + d(1,3)$ on resout l'equation {{0,3},3} qui est maintenant AA:= - (d(3,5) + d(3,4)*a)$ Unknowns: {d(3,5),d(3,4),a} Unknowns: {d(3,5),d(3,4),a} bonne inconnue W:=d(3,5)$ sa valeur doit etre WW:= - d(3,4)*a$ on resout l'equation {{0,3},4} qui est maintenant AA:= - d(4,5) - d(4,4)*a + d( 3,3)*a + d(0,0)*a$ Unknowns: {d(4,5),d(4,4),d(3,3),d(0,0),a} Unknowns: {d(4,5),d(4,4),d(3,3),d(0,0),a} bonne inconnue W:=d(4,5)$ sa valeur doit etre WW:=a*( - d(4,4) + d(3,3) + d(0,0))$ on resout l'equation {{0,3},5} qui est maintenant AA:= - d(5,5) - d(5,4)*a - d( 4,4)*a*b + d(3,3)*a*b + d(3,3) + d(2,3)*b + d(0,0)*a*b + d(0,0)$ Unknowns: {d(5,5),d(5,4),d(4,4),d(3,3),d(2,3),d(0,0),a,b} Unknowns: {d(5,5),d(5,4),d(4,4),d(3,3),d(2,3),d(0,0),a,b} bonne inconnue W:=d(5,5)$ sa valeur doit etre WW:= - d(5,4)*a - d(4,4)*a*b + d(3,3)*a*b + d(3,3) + d(2,3)* b + d(0,0)*a*b + d(0,0)$ on resout l'equation {{0,3},6} qui est maintenant AA:= - d(6,5) - d(6,4)*a + d( 5,3)*a - d(5,3) - d(2,0)$ Unknowns: {d(6,5),d(6,4),d(5,3),d(2,0),a} Unknowns: {d(6,5),d(6,4),d(5,3),d(2,0),a} bonne inconnue W:=d(6,5)$ sa valeur doit etre WW:= - d(6,4)*a + d(5,3)*a - d(5,3) - d(2,0)$ on resout l'equation {{0,4},2} qui est maintenant AA:=d(1,4)$ Unknown: d(1,4) Unknown: d(1,4) bonne inconnue W:=d(1,4)$ sa valeur doit etre WW:=0$ on resout l'equation {{0,4},4} qui est maintenant AA:=d(3,4)*a$ Unknowns: {d(3,4),a} Unknowns: {d(3,4),a} pas de selection possible de variable a coefficient independant des xi dans d(3, 4)*a on resout l'equation {{0,4},5} qui est maintenant AA:=d(3,4) + d(2,4)*b$ Unknowns: {d(3,4),d(2,4),b} Unknowns: {d(3,4),d(2,4),b} bonne inconnue W:=d(3,4)$ sa valeur doit etre WW:= - d(2,4)*b$ on resout l'equation {{0,4},6} qui est maintenant AA:=d(5,4)*a - d(5,4) - d(4,4 )*a*b + d(3,3)*a*b + d(0,0)*a*b$ Unknowns: {d(5,4),d(4,4),d(3,3),d(0,0),a,b} Unknowns: {d(5,4),d(4,4),d(3,3),d(0,0),a,b} pas de selection possible de variable a coefficient independant des xi dans d(5, 4)*a - d(5,4) - d(4,4)*a*b + d(3,3)*a*b + d(0,0)*a*b on resout l'equation {{0,5},0} qui est maintenant AA:=d(0,6)*( - a + 1)$ Unknowns: {d(0,6),a} Unknowns: {d(0,6),a} pas de selection possible de variable a coefficient independant des xi dans d(0, 6)*( - a + 1) on resout l'equation {{0,5},1} qui est maintenant AA:=d(1,6)*( - a + 1)$ Unknowns: {d(1,6),a} Unknowns: {d(1,6),a} pas de selection possible de variable a coefficient independant des xi dans d(1, 6)*( - a + 1) on resout l'equation {{0,5},2} qui est maintenant AA:=d(2,6)*( - a + 1)$ Unknowns: {d(2,6),a} Unknowns: {d(2,6),a} pas de selection possible de variable a coefficient independant des xi dans d(2, 6)*( - a + 1) on resout l'equation {{0,5},3} qui est maintenant AA:=d(3,6)*( - a + 1)$ Unknowns: {d(3,6),a} Unknowns: {d(3,6),a} pas de selection possible de variable a coefficient independant des xi dans d(3, 6)*( - a + 1) on resout l'equation {{0,5},4} qui est maintenant AA:= - d(4,6)*a + d(4,6) + d( 2,4)*a**2*b$ Unknowns: {d(4,6),d(2,4),a,b} Unknowns: {d(4,6),d(2,4),a,b} pas de selection possible de variable a coefficient independant des xi dans - d (4,6)*a + d(4,6) + d(2,4)*a**2*b on resout l'equation {{0,5},5} qui est maintenant AA:= - d(5,6)*a + d(5,6) + d( 1,3)*b$ Unknowns: {d(5,6),d(1,3),a,b} Unknowns: {d(5,6),d(1,3),a,b} pas de selection possible de variable a coefficient independant des xi dans - d (5,6)*a + d(5,6) + d(1,3)*b on resout l'equation {{0,5},6} qui est maintenant AA:= - d(6,6)*a + d(6,6) - d( 5,4)*a**2 + d(5,4)*a - d(4,4)*a**2*b + d(4,4)*a*b + d(3,3)*a**2*b - d(3,3)*a*b + d(3,3)*a - d(3,3) + d(2,3)*a*b - d(2,3)*b + d(0,0)*a**2*b - d(0,0)*a*b + 2*d(0, 0)*a - 2*d(0,0)$ Unknowns: {d(6,6),d(5,4),d(4,4),d(3,3),d(2,3),d(0,0),a,b} Unknowns: {d(6,6),d(5,4),d(4,4),d(3,3),d(2,3),d(0,0),a,b} pas de selection possible de variable a coefficient independant des xi dans - d (6,6)*a + d(6,6) - d(5,4)*a**2 + d(5,4)*a - d(4,4)*a**2*b + d(4,4)*a*b + d(3,3)* a**2*b - d(3,3)*a*b + d(3,3)*a - d(3,3) + d(2,3)*a*b - d(2,3)*b + d(0,0)*a**2*b - d(0,0)*a*b + 2*d(0,0)*a - 2*d(0,0) on resout l'equation {{0,6},2} qui est maintenant AA:=d(1,6)$ Unknown: d(1,6) Unknown: d(1,6) bonne inconnue W:=d(1,6)$ sa valeur doit etre WW:=0$ on resout l'equation {{0,6},4} qui est maintenant AA:=d(3,6)*a$ Unknowns: {d(3,6),a} Unknowns: {d(3,6),a} pas de selection possible de variable a coefficient independant des xi dans d(3, 6)*a on resout l'equation {{0,6},5} qui est maintenant AA:=d(3,6) + d(2,6)*b$ Unknowns: {d(3,6),d(2,6),b} Unknowns: {d(3,6),d(2,6),b} bonne inconnue W:=d(3,6)$ sa valeur doit etre WW:= - d(2,6)*b$ on resout l'equation {{0,6},6} qui est maintenant AA:=d(5,6)*(a - 1)$ Unknowns: {d(5,6),a} Unknowns: {d(5,6),a} pas de selection possible de variable a coefficient independant des xi dans d(5, 6)*(a - 1) on resout l'equation {{1,2},0} qui est maintenant AA:= - d(0,4)$ Unknown: d(0,4) Unknown: d(0,4) bonne inconnue W:=d(0,4)$ sa valeur doit etre WW:=0$ on resout l'equation {{1,2},2} qui est maintenant AA:= - d(2,4)$ Unknown: d(2,4) Unknown: d(2,4) bonne inconnue W:=d(2,4)$ sa valeur doit etre WW:=0$ on resout l'equation {{1,2},4} qui est maintenant AA:= - d(4,4) + 2*d(1,1) + d( 0,0)$ Unknowns: {d(4,4),d(1,1),d(0,0)} Unknowns: {d(4,4),d(1,1),d(0,0)} bonne inconnue W:=d(4,4)$ sa valeur doit etre WW:=2*d(1,1) + d(0,0)$ on resout l'equation {{1,2},5} qui est maintenant AA:= - d(5,4) + d(0,1)*b$ Unknowns: {d(5,4),d(0,1),b} Unknowns: {d(5,4),d(0,1),b} bonne inconnue W:=d(5,4)$ sa valeur doit etre WW:=d(0,1)*b$ on resout l'equation {{1,2},6} qui est maintenant AA:= - d(6,4) + d(3,1)*a + d( 3,1) - d(2,0)$ Unknowns: {d(6,4),d(3,1),d(2,0),a} Unknowns: {d(6,4),d(3,1),d(2,0),a} bonne inconnue W:=d(6,4)$ sa valeur doit etre WW:=d(3,1)*a + d(3,1) - d(2,0)$ on resout l'equation {{1,3},2} qui est maintenant AA:= - (d(1,3) + d(0,3))$ Unknowns: {d(1,3),d(0,3)} Unknowns: {d(1,3),d(0,3)} bonne inconnue W:=d(1,3)$ sa valeur doit etre WW:= - d(0,3)$ on resout l'equation {{1,3},4} qui est maintenant AA:= - d(3,3)*a + d(2,3) + 2* d(1,1)*a + d(0,1)*a$ Unknowns: {d(3,3),d(2,3),d(1,1),d(0,1),a} Unknowns: {d(3,3),d(2,3),d(1,1),d(0,1),a} bonne inconnue W:=d(2,3)$ sa valeur doit etre WW:=a*(d(3,3) - 2*d(1,1) - d(0,1))$ on resout l'equation {{1,3},5} qui est maintenant AA:= - 2*d(3,3)*a*b + 4*d(1,1 )*a*b + d(1,1) + 2*d(0,1)*a*b + d(0,1) - d(0,0)$ Unknowns: {d(3,3),d(1,1),d(0,1),d(0,0),a,b} Unknowns: {d(3,3),d(1,1),d(0,1),d(0,0),a,b} bonne inconnue W:=d(0,0)$ sa valeur doit etre WW:= - 2*d(3,3)*a*b + 4*d(1,1)*a*b + d(1,1) + 2*d(0,1)*a*b + d(0,1)$ on resout l'equation {{1,3},6} qui est maintenant AA:= - d(5,3)*a + d(5,3) + d( 4,3) + d(3,1)*a**2 + d(3,1)*a - d(2,1) - d(2,0)*a + d(2,0)$ Unknowns: {d(5,3),d(4,3),d(3,1),d(2,1),d(2,0),a} Unknowns: {d(5,3),d(4,3),d(3,1),d(2,1),d(2,0),a} bonne inconnue W:=d(4,3)$ sa valeur doit etre WW:=d(5,3)*a - d(5,3) - d(3,1)*a**2 - d(3,1)*a + d(2,1) + d( 2,0)*a - d(2,0)$ on resout l'equation {{1,4},0} qui est maintenant AA:= - d(0,6)$ Unknown: d(0,6) Unknown: d(0,6) bonne inconnue W:=d(0,6)$ sa valeur doit etre WW:=0$ on resout l'equation {{1,4},2} qui est maintenant AA:= - d(2,6)$ Unknown: d(2,6) Unknown: d(2,6) bonne inconnue W:=d(2,6)$ sa valeur doit etre WW:=0$ on resout l'equation {{1,4},4} qui est maintenant AA:= - d(4,6)$ Unknown: d(4,6) Unknown: d(4,6) bonne inconnue W:=d(4,6)$ sa valeur doit etre WW:=0$ on resout l'equation {{1,4},5} qui est maintenant AA:= - d(5,6)$ Unknown: d(5,6) Unknown: d(5,6) bonne inconnue W:=d(5,6)$ sa valeur doit etre WW:=0$ on resout l'equation {{1,4},6} qui est maintenant AA:= - d(6,6) - 2*d(3,3)*a*b + 4*d(1,1)*a*b + 4*d(1,1) + 2*d(0,1)*a*b + d(0,1)$ Unknowns: {d(6,6),d(3,3),d(1,1),d(0,1),a,b} Unknowns: {d(6,6),d(3,3),d(1,1),d(0,1),a,b} bonne inconnue W:=d(6,6)$ sa valeur doit etre WW:= - 2*d(3,3)*a*b + 4*d(1,1)*a*b + 4*d(1,1) + 2*d(0,1)*a*b + d(0,1)$ on resout l'equation {{1,5},4} qui est maintenant AA:= - d(0,3)$ Unknown: d(0,3) Unknown: d(0,3) bonne inconnue W:=d(0,3)$ sa valeur doit etre WW:=0$ on resout l'equation {{1,5},6} qui est maintenant AA:=d(3,3)*a - 2*d(1,1)*a + d (0,1)*a - d(0,1)$ Unknowns: {d(3,3),d(1,1),d(0,1),a} Unknowns: {d(3,3),d(1,1),d(0,1),a} pas de selection possible de variable a coefficient independant des xi dans d(3, 3)*a - 2*d(1,1)*a + d(0,1)*a - d(0,1) on resout l'equation {{2,3},6} qui est maintenant AA:= - d(3,3) + 2*d(1,1)$ Unknowns: {d(3,3),d(1,1)} Unknowns: {d(3,3),d(1,1)} bonne inconnue W:=d(3,3)$ sa valeur doit etre WW:=2*d(1,1)$ Derivation equations to cancel (Reduce output) : \\{{{{0,1},0},0}, {{{0,1},1},0}, {{{0,1},2},0}, {{{0,1},3},0}, {{{0,1},4},0}, {{{0,1},5},0}, {{{0,1},6},0}, {{{0,2},0},0}, {{{0,2},1},0}, {{{0,2},2},0}, {{{0,2},3},0}, {{{0,2},4},0}, {{{0,2},5},(4*a*b + 1)*d(0,1)*b}, {{{0,2},6}, d(3,1)*a - d(3,1) + d(3,0) - (a - 1)*d(5,3)*b - (d(3,0) - d(2,1)*b)*(a - 1) + (( a + 1)*d(3,1)*a - (a - 1)*d(2,0))*b}, {{{0,3},0},0}, {{{0,3},1},0}, {{{0,3},2},0}, {{{0,3},3},0}, {{{0,3},4},0}, {{{0,3},5},0}, {{{0,3},6},0}, {{{0,4},2},0}, {{{0,4},4},0}, {{{0,4},5},0}, {{{0,4},6},(a - 1)*d(0,1)*b}, {{{0,5},0},0}, {{{0,5},1},0}, {{{0,5},2},0}, {{{0,5},3},0}, {{{0,5},4},0}, {{{0,5},5},0}, {{{0,5},6},(a - 1)*d(0,1)}, {{{0,6},2},0}, {{{0,6},4},0}, {{{0,6},5},0}, {{{0,6},6},0}, {{{1,2},0},0}, {{{1,2},1},0}, {{{1,2},2},0}, {{{1,2},3},0}, {{{1,2},4},0}, {{{1,2},5},0}, {{{1,2},6},0}, {{{1,3},0},0}, {{{1,3},1},0}, {{{1,3},2},0}, {{{1,3},3},0}, {{{1,3},4},0}, {{{1,3},5},0}, {{{1,3},6},0}, {{{1,4},0},0}, {{{1,4},1},0}, {{{1,4},2},0}, {{{1,4},3},0}, {{{1,4},4},0}, {{{1,4},5},0}, {{{1,4},6},0}, {{{1,5},2},0}, {{{1,5},4},0}, {{{1,5},5},0}, {{{1,5},6},(a - 1)*d(0,1)}, {{{1,6},2},0}, {{{1,6},4},0}, {{{1,6},5},0}, {{{1,6},6},0}, {{{2,3},0},0}, {{{2,3},1},0}, {{{2,3},2},0}, {{{2,3},3},0}, {{{2,3},4},0}, {{{2,3},5},0}, {{{2,3},6},0}, {{{2,4},4},0}, {{{2,4},5},0}, {{{2,4},6},0}, {{{2,5},4},0}, {{{2,5},5},0}, {{{2,5},6},0}, {{{2,6},4},0}, {{{2,6},5},0}, {{{2,6},6},0}, {{{3,4},4},0}, {{{3,4},5},0}, {{{3,4},6},0}, {{{3,5},4},0}, {{{3,5},5},0}, {{{3,5},6},0}, {{{3,6},4},0}, {{{3,6},5},0}, {{{3,6},6},0}, {{{4,5},6},0}, {{{4,6},6},0}, {{{5,6},6},0}}$ Il y a une phase 2$ Si a neq 1, d(0,1):=0$ collect_eq:={{{{0,1},0},0}, {{{0,1},1},0}, {{{0,1},2},0}, {{{0,1},3},0}, {{{0,1},4},0}, {{{0,1},5},0}, {{{0,1},6},0}, {{{0,2},0},0}, {{{0,2},1},0}, {{{0,2},2},0}, {{{0,2},3},0}, {{{0,2},4},0}, {{{0,2},5},0}, {{{0,2},6},0}, {{{0,3},0},0}, {{{0,3},1},0}, {{{0,3},2},0}, {{{0,3},3},0}, {{{0,3},4},0}, {{{0,3},5},0}, {{{0,3},6},0}, {{{0,4},2},0}, {{{0,4},4},0}, {{{0,4},5},0}, {{{0,4},6},0}, {{{0,5},0},0}, {{{0,5},1},0}, {{{0,5},2},0}, {{{0,5},3},0}, {{{0,5},4},0}, {{{0,5},5},0}, {{{0,5},6},0}, {{{0,6},2},0}, {{{0,6},4},0}, {{{0,6},5},0}, {{{0,6},6},0}, {{{1,2},0},0}, {{{1,2},1},0}, {{{1,2},2},0}, {{{1,2},3},0}, {{{1,2},4},0}, {{{1,2},5},0}, {{{1,2},6},0}, {{{1,3},0},0}, {{{1,3},1},0}, {{{1,3},2},0}, {{{1,3},3},0}, {{{1,3},4},0}, {{{1,3},5},0}, {{{1,3},6},0}, {{{1,4},0},0}, {{{1,4},1},0}, {{{1,4},2},0}, {{{1,4},3},0}, {{{1,4},4},0}, {{{1,4},5},0}, {{{1,4},6},0}, {{{1,5},2},0}, {{{1,5},4},0}, {{{1,5},5},0}, {{{1,5},6},0}, {{{1,6},2},0}, {{{1,6},4},0}, {{{1,6},5},0}, {{{1,6},6},0}, {{{2,3},0},0}, {{{2,3},1},0}, {{{2,3},2},0}, {{{2,3},3},0}, {{{2,3},4},0}, {{{2,3},5},0}, {{{2,3},6},0}, {{{2,4},4},0}, {{{2,4},5},0}, {{{2,4},6},0}, {{{2,5},4},0}, {{{2,5},5},0}, {{{2,5},6},0}, {{{2,6},4},0}, {{{2,6},5},0}, {{{2,6},6},0}, {{{3,4},4},0}, {{{3,4},5},0}, {{{3,4},6},0}, {{{3,5},4},0}, {{{3,5},5},0}, {{{3,5},6},0}, {{{3,6},4},0}, {{{3,6},5},0}, {{{3,6},6},0}, {{{4,5},6},0}, {{{4,6},6},0}, {{{5,6},6},0}}$ derivation generique de gtildedelta:$ MATD:= mat((d(1,1),0,0,0,0,0,0),(0,d(1,1),0,0,0,0,0),(d(2,0),d(2,1),2*d(1,1),0,0,0,0),( d(3,0),d(3,1),0,2*d(1,1),0,0,0),(d(4,0),d(4,1),d(3,1)*a - d(2,0),( - (d(3,0)*a - 2*d(3,0) - d(2,1)*a*b - (a - 1)*d(3,1)))/b,3*d(1,1),0,0),(d(5,0),d(5,1), - (d(3 ,0) - d(2,1)*b - d(3,1)),((a**2*b + a*b + a - 1)*d(3,1) - (a - 2)*d(3,0) + (d(2, 1) - d(2,0))*(a - 1)*b)/((a - 1)*b),0,3*d(1,1),0),(d(6,0),d(6,1),d(5,1)*a - d(5, 1) - d(4,0),d(6,3),d(3,1)*a + d(3,1) - d(2,0),((a - 1)*d(2,1)*b - (a - 2)*d(3,0) + (a - 1)*d(3,1))/b,4*d(1,1)))$ pour delta:= mat((0,0,0,0,0,0),(1,0,0,0,0,0),(0,0,0,0,0,0),(0,0,a,0,0,0),(0,b,1,0,0,0),(0,0,0 ,0,a - 1,0))$ pour shortformdelta:={1, ss, 0, 0, ss, a, ss, b, 1, ss, 0, 0}$ Unknowns: {d(6,3), d(6,1), d(6,0), d(5,1), d(5,0), d(4,1), d(4,0), d(3,1), d(3,0), d(2,1), d(2,0), d(1,1), a, b} Unknowns: {d(6,3), d(6,1), d(6,0), d(5,1), d(5,0), d(4,1), d(4,0), d(3,1), d(3,0), d(2,1), d(2,0), d(1,1), a, b} listparametresMATD{d(6,3), d(6,1), d(6,0), d(5,1), d(5,0), d(4,1), d(4,0), d(3,1), d(3,0), d(2,1), d(2,0), d(1,1)}$ dim Der(gtildedelta):=12$ un element t1 d'un tore $ t1:=D(1,1)$ t1:= [1 0 0 0 0 0 0] [ ] [0 1 0 0 0 0 0] [ ] [0 0 2 0 0 0 0] [ ] [0 0 0 2 0 0 0] [ ] [0 0 0 0 3 0 0] [ ] [0 0 0 0 0 3 0] [ ] [0 0 0 0 0 0 4] t1 est un tore maximal. matrice de passage de la base X(0)=delta, X(1),..., X(6) a une base diagonali\ sant le tore maximal: on peut prendre P:= [1 0 0 0 0 0 0] [ ] [0 1 0 0 0 0 0] [ ] [0 0 1 0 0 0 0] [ ] [0 0 0 1 0 0 0] [ ] [0 0 0 0 1 0 0] [ ] [0 0 0 0 0 1 0] [ ] [0 0 0 0 0 0 1] P**(-1)*t1*P:= [1 0 0 0 0 0 0] [ ] [0 1 0 0 0 0 0] [ ] [0 0 2 0 0 0 0] [ ] [0 0 0 2 0 0 0] [ ] [0 0 0 0 3 0 0] [ ] [0 0 0 0 0 3 0] [ ] [0 0 0 0 0 0 4] matrice des derivations dans cette base diagonalisante Y(1),...,Y(7): P**(-1)*MATD*P:= mat((d(1,1),0,0,0,0,0,0), (0,d(1,1),0,0,0,0,0), (d(2,0),d(2,1),2*d(1,1),0,0,0,0), (d(3,0),d(3,1),0,2*d(1,1),0,0,0), (d(4,0),d(4,1),d(3,1)*a - d(2,0), - (d(3,0)*a - 2*d(3,0) - d(2,1)*a*b - (a - 1)*d(3,1)) --------------------------------------------------------,3*d(1,1),0,0), b (d(5,0),d(5,1), - (d(3,0) - d(2,1)*b - d(3,1)),((d(2,1) - d(2,0))*(a - 1)*b 2 - (a - 2)*d(3,0) + (a *b + a*b + a - 1)*d(3,1))/((a - 1)*b),0,3*d(1,1), 0), (d(6,0),d(6,1),d(5,1)*a - d(5,1) - d(4,0),d(6,3),d(3,1)*a + d(3,1) - d(2,0), (a - 1)*d(2,1)*b - (a - 2)*d(3,0) + (a - 1)*d(3,1) ----------------------------------------------------,4*d(1,1))) b PP**(-1)*MATD*PP:= mat((d(1,1),0,0,0,0,0,0), (0,d(1,1),0,0,0,0,0), (d(2,0),d(2,1),2*d(1,1),0,0,0,0), (d(3,0),d(3,1),0,2*d(1,1),0,0,0), (d(4,0),d(4,1),d(3,1)*a - d(2,0), - (d(3,0)*a - 2*d(3,0) - d(2,1)*a*b - (a - 1)*d(3,1)) --------------------------------------------------------,3*d(1,1),0,0), b (d(5,0),d(5,1), - (d(3,0) - d(2,1)*b - d(3,1)),((d(2,1) - d(2,0))*(a - 1)*b 2 - (a - 2)*d(3,0) + (a *b + a*b + a - 1)*d(3,1))/((a - 1)*b),0,3*d(1,1), 0), (d(6,0),d(6,1),d(5,1)*a - d(5,1) - d(4,0),d(6,3),d(3,1)*a + d(3,1) - d(2,0), (a - 1)*d(2,1)*b - (a - 2)*d(3,0) + (a - 1)*d(3,1) ----------------------------------------------------,4*d(1,1))) b avec PP:=P*Q:= [1 0 0 0 0 0 0] [ ] [0 1 0 0 0 0 0] [ ] [0 0 1 0 0 0 0] [ ] [0 0 0 1 0 0 0] [ ] [0 0 0 0 1 0 0] [ ] [0 0 0 0 0 1 0] [ ] [0 0 0 0 0 0 1] MATDDIAGONALISE:= mat((d(1,1),0,0,0,0,0,0), (0,d(1,1),0,0,0,0,0), (d(2,0),d(2,1),2*d(1,1),0,0,0,0), (d(3,0),d(3,1),0,2*d(1,1),0,0,0), (d(4,0),d(4,1),d(3,1)*a - d(2,0), - (d(3,0)*a - 2*d(3,0) - d(2,1)*a*b - (a - 1)*d(3,1)) --------------------------------------------------------,3*d(1,1),0,0), b (d(5,0),d(5,1), - (d(3,0) - d(2,1)*b - d(3,1)),((d(2,1) - d(2,0))*(a - 1)*b 2 - (a - 2)*d(3,0) + (a *b + a*b + a - 1)*d(3,1))/((a - 1)*b),0,3*d(1,1), 0), (d(6,0),d(6,1),d(5,1)*a - d(5,1) - d(4,0),d(6,3),d(3,1)*a + d(3,1) - d(2,0), (a - 1)*d(2,1)*b - (a - 2)*d(3,0) + (a - 1)*d(3,1) ----------------------------------------------------,4*d(1,1))) b on voit apparaitre les poids sur la diagonale ladiag := {{1,d(1,1)}, {2,d(1,1)}, {3,2*d(1,1)}, {4,2*d(1,1)}, {5,3*d(1,1)}, {6,3*d(1,1)}, {7,4*d(1,1)}} calcul de relations de commutation de la base diaY(j) diagonalisant le tore listcommutateursdesx := {{{0,1},x(2)}, {{0,2},b*x(5)}, {{0,3},x(5) + x(4)*a}, {{0,4},0}, {{0,5},(a - 1)*x(6)}, {{0,6},0}, {{1,2},x(4)}, {{1,3},x(5)}, {{1,4},x(6)}, {{1,5},0}, {{1,6},0}, {{2,3}, - x(6)}, {{2,4},0}, {{2,5},0}, {{2,6},0}, {{3,4},0}, {{3,5},0}, {{3,6},0}, {{4,5},0}, {{4,6},0}, {{5,6},0}} *** diay declared operator diaY(1):=x(0) diaY(2):=x(1) diaY(3):=x(2) diaY(4):=x(3) diaY(5):=x(4) diaY(6):=x(5) diaY(7):=x(6) *** yy declared operator *** diadiay declared operator liste des commutateurs des diaY(i) := (diadiaY=diaY {{{1,2},diadiay(3)}, {{1,3},diadiay(6)*b}, {{1,4},diadiay(6) + diadiay(5)*a}, {{1,5},0}, {{1,6},(a - 1)*diadiay(7)}, {{1,7},0}, {{2,3},diadiay(5)}, {{2,4},diadiay(6)}, {{2,5},diadiay(7)}, {{2,6},0}, {{2,7},0}, {{3,4}, - diadiay(7)}, {{3,5},0}, {{3,6},0}, {{3,7},0}, {{4,5},0}, {{4,6},0}, {{4,7},0}, {{5,6},0}, {{5,7},0}, {{6,7},0}} On obtient, et cela pour a neq 1 (voir feuilles manuscrites) 1) Pour b= -(a-1)/(2a-1)**2 et a neq 1/2: les relations de commutation de g_\ {7,1.2(ii)}. 2) Pour a= -1/2 ou a neq -1/2 et b= -(a-1)/(2a-1)**2: les relations de commuta\ tion de g_{7,1.2(i_L)} avec L:=-(1/beta)* (3beta*a*b -beta*b +beta**3*b +sqrt(b)*sqrt(a-1))/(a*b -beta**2*\ b*(a-1) -beta*sqrt(b)*sqrt(a-1)) 2 (3*a + beta - 1)*b*beta + sqrt(b)*sqrt(a - 1) L:=----------------------------------------------------------- 2 2 ((a*beta - a - beta )*b + sqrt(b)*sqrt(a - 1)*beta)*beta avec beta racine de f et pas racine de g *** f declared operator f(x) := x**2 -2*x*sqrt(b)*(2a-1)/sqrt(a-1) -1 *** g declared operator g(x) := x**2 + x/(sqrt(b)*sqrt(a-1)) -a/a-1 2 sqrt(a - 1)*x - sqrt(a - 1) - 4*sqrt(b)*a*x + 2*sqrt(b)*x f(x):=------------------------------------------------------------ sqrt(a - 1) 2 sqrt(b)*sqrt(a - 1)*x - 2*sqrt(b)*sqrt(a - 1) + x g(x):=---------------------------------------------------- sqrt(b)*sqrt(a - 1)