generic derivation : delta:=
mat((xi(1,1),0,0,0,0,0),(xi(2,1),xi(2,2),xi(2,3),0,0,0),(xi(3,1),xi(3,2),xi(3,3)
,0,0,0),(xi(4,1),xi(4,2),xi(4,3),xi(2,2) + xi(1,1),xi(2,3),xi(4,6)),(xi(5,1),xi(
5,2),xi(5,3),xi(3,2),xi(3,3) + xi(1,1),xi(5,6)),(xi(6,1),xi(6,2),xi(6,3),0,0,xi(
6,6)))$

        [0  0  0  0  0  0]
        [                ]
        [0  0  0  0  0  0]
        [                ]
        [0  0  0  0  0  0]
adx1 := [                ]
        [0  1  0  0  0  0]
        [                ]
        [0  0  1  0  0  0]
        [                ]
        [0  0  0  0  0  0]


        [0   0  0  0  0  0]
        [                 ]
        [0   0  0  0  0  0]
        [                 ]
        [0   0  0  0  0  0]
adx2 := [                 ]
        [-1  0  0  0  0  0]
        [                 ]
        [0   0  0  0  0  0]
        [                 ]
        [0   0  0  0  0  0]


        [0   0  0  0  0  0]
        [                 ]
        [0   0  0  0  0  0]
        [                 ]
        [0   0  0  0  0  0]
adx3 := [                 ]
        [0   0  0  0  0  0]
        [                 ]
        [-1  0  0  0  0  0]
        [                 ]
        [0   0  0  0  0  0]


The generic nilpotent derivation : the eigenvalues are 0

xi(1,1):=0

xi(6,6):=0

And the matrix A:=(xi(2,2),xi(2,3)),(xi(3,2),xi(3,3)) is nilpotent

We hence get 2 cases according to whether A neq 0 or A=0.

We consider here the case 1 where A neq 0.

In that case, one may suppose A:=((0,1),(0,0)).

xi(2,2):=0

xi(2,3):=1

xi(3,2):=0

xi(3,3):=0

by subtracting adjoints one then may suppose:

xi(4,1):=0,xi(4,2):=0,xi(5,1):=0

delta:=

[   0        0        0     0  0     0   ]
[                                        ]
[xi(2,1)     0        1     0  0     0   ]
[                                        ]
[xi(3,1)     0        0     0  0     0   ]
[                                        ]
[   0        0     xi(4,3)  0  1  xi(4,6)]
[                                        ]
[   0     xi(5,2)  xi(5,3)  0  0  xi(5,6)]
[                                        ]
[xi(6,1)  xi(6,2)  xi(6,3)  0  0     0   ]


We denote this delta by the shortform

shortformdelta:={xi(2,1),

                 xi(3,1),

                 xi(6,1),

                 ss,

                 xi(5,2),

                 xi(6,2),

                 ss,

                 xi(4,3),

                 xi(5,3),

                 xi(6,3),

                 ss,

                 xi(4,6),

                 xi(5,6)}

paramindexeslist:={{2,1},

   {3,1},

   {6,1},

   {5,2},

   {6,2},

   {4,3},

   {5,3},

   {6,3},

   {4,6},

   {5,6}}

a:=1$

b:=1$

delta:=
mat((0,0,0,0,0,0),(0,0,1,0,0,0),(0,0,0,0,0,0),(0,0,0,0,1,0),(0,1,0,0,0,1),(1,0,0
,0,0,0))$

shortformdelta:={0,0,1,ss,1,0,ss,0,0,0,ss,0,1}$

on resout l'equation {{0,1},0} qui est  maintenant AA:= - d(0,6)$

Unknown: d(0,6)
Unknown: d(0,6)
bonne inconnue W:=d(0,6)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,1},1} qui est  maintenant AA:= - d(1,6)$

Unknown: d(1,6)
Unknown: d(1,6)
bonne inconnue W:=d(1,6)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,1},2} qui est  maintenant AA:=d(3,1) - d(2,6)$

Unknowns: {d(3,1),d(2,6)}
Unknowns: {d(3,1),d(2,6)}
bonne inconnue W:=d(3,1)$

sa valeur doit etre WW:=d(2,6)$

on resout l'equation {{0,1},3} qui est  maintenant AA:= - d(3,6)$

Unknown: d(3,6)
Unknown: d(3,6)
bonne inconnue W:=d(3,6)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,1},4} qui est  maintenant AA:=d(5,1) - d(4,6) - d(2,0)$

Unknowns: {d(5,1),d(4,6),d(2,0)}
Unknowns: {d(5,1),d(4,6),d(2,0)}
bonne inconnue W:=d(5,1)$

sa valeur doit etre WW:=d(4,6) + d(2,0)$

on resout l'equation {{0,1},5} qui est  maintenant AA:=d(6,1) - d(5,6) - d(3,0) 
+ d(2,1)$

Unknowns: {d(6,1),d(5,6),d(3,0),d(2,1)}
Unknowns: {d(6,1),d(5,6),d(3,0),d(2,1)}
bonne inconnue W:=d(6,1)$

sa valeur doit etre WW:=d(5,6) + d(3,0) - d(2,1)$

on resout l'equation {{0,1},6} qui est  maintenant AA:= - d(6,6) + d(1,1) + d(0,
0)$

Unknowns: {d(6,6),d(1,1),d(0,0)}
Unknowns: {d(6,6),d(1,1),d(0,0)}
bonne inconnue W:=d(6,6)$

sa valeur doit etre WW:=d(1,1) + d(0,0)$

on resout l'equation {{0,2},0} qui est  maintenant AA:= - d(0,5)$

Unknown: d(0,5)
Unknown: d(0,5)
bonne inconnue W:=d(0,5)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,2},1} qui est  maintenant AA:= - d(1,5)$

Unknown: d(1,5)
Unknown: d(1,5)
bonne inconnue W:=d(1,5)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,2},2} qui est  maintenant AA:=d(3,2) - d(2,5)$

Unknowns: {d(3,2),d(2,5)}
Unknowns: {d(3,2),d(2,5)}
bonne inconnue W:=d(3,2)$

sa valeur doit etre WW:=d(2,5)$

on resout l'equation {{0,2},3} qui est  maintenant AA:= - d(3,5)$

Unknown: d(3,5)
Unknown: d(3,5)
bonne inconnue W:=d(3,5)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,2},4} qui est  maintenant AA:=d(5,2) - d(4,5) + d(1,0)$

Unknowns: {d(5,2),d(4,5),d(1,0)}
Unknowns: {d(5,2),d(4,5),d(1,0)}
bonne inconnue W:=d(5,2)$

sa valeur doit etre WW:=d(4,5) - d(1,0)$

on resout l'equation {{0,2},5} qui est  maintenant AA:=d(6,2) - d(5,5) + d(2,2) 
+ d(0,0)$

Unknowns: {d(6,2),d(5,5),d(2,2),d(0,0)}
Unknowns: {d(6,2),d(5,5),d(2,2),d(0,0)}
bonne inconnue W:=d(6,2)$

sa valeur doit etre WW:=d(5,5) - d(2,2) - d(0,0)$

on resout l'equation {{0,2},6} qui est  maintenant AA:= - d(6,5) + d(1,2)$

Unknowns: {d(6,5),d(1,2)}
Unknowns: {d(6,5),d(1,2)}
bonne inconnue W:=d(6,5)$

sa valeur doit etre WW:=d(1,2)$

on resout l'equation {{0,3},0} qui est  maintenant AA:= - d(0,2)$

Unknown: d(0,2)
Unknown: d(0,2)
bonne inconnue W:=d(0,2)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,3},1} qui est  maintenant AA:= - d(1,2)$

Unknown: d(1,2)
Unknown: d(1,2)
bonne inconnue W:=d(1,2)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,3},2} qui est  maintenant AA:=d(3,3) - d(2,2) + d(0,0)$

Unknowns: {d(3,3),d(2,2),d(0,0)}
Unknowns: {d(3,3),d(2,2),d(0,0)}
bonne inconnue W:=d(3,3)$

sa valeur doit etre WW:=d(2,2) - d(0,0)$

on resout l'equation {{0,3},3} qui est  maintenant AA:= - d(2,5)$

Unknown: d(2,5)
Unknown: d(2,5)
bonne inconnue W:=d(2,5)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,3},4} qui est  maintenant AA:=d(5,3) - d(4,2)$

Unknowns: {d(5,3),d(4,2)}
Unknowns: {d(5,3),d(4,2)}
bonne inconnue W:=d(5,3)$

sa valeur doit etre WW:=d(4,2)$

on resout l'equation {{0,3},5} qui est  maintenant AA:=d(6,3) - d(4,5) + d(2,3) 
+ 2*d(1,0)$

Unknowns: {d(6,3),d(4,5),d(2,3),d(1,0)}
Unknowns: {d(6,3),d(4,5),d(2,3),d(1,0)}
bonne inconnue W:=d(6,3)$

sa valeur doit etre WW:=d(4,5) - d(2,3) - 2*d(1,0)$

on resout l'equation {{0,3},6} qui est  maintenant AA:= - d(5,5) + d(2,2) + d(1,
3) + d(0,0)$

Unknowns: {d(5,5),d(2,2),d(1,3),d(0,0)}
Unknowns: {d(5,5),d(2,2),d(1,3),d(0,0)}
bonne inconnue W:=d(5,5)$

sa valeur doit etre WW:=d(2,2) + d(1,3) + d(0,0)$

on resout l'equation {{0,4},2} qui est  maintenant AA:=d(3,4)$

Unknown: d(3,4)
Unknown: d(3,4)
bonne inconnue W:=d(3,4)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,4},4} qui est  maintenant AA:=d(5,4)$

Unknown: d(5,4)
Unknown: d(5,4)
bonne inconnue W:=d(5,4)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,4},5} qui est  maintenant AA:=d(6,4) + d(2,4)$

Unknowns: {d(6,4),d(2,4)}
Unknowns: {d(6,4),d(2,4)}
bonne inconnue W:=d(6,4)$

sa valeur doit etre WW:= - d(2,4)$

on resout l'equation {{0,4},6} qui est  maintenant AA:=d(1,4)$

Unknown: d(1,4)
Unknown: d(1,4)
bonne inconnue W:=d(1,4)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,5},0} qui est  maintenant AA:= - d(0,4)$

Unknown: d(0,4)
Unknown: d(0,4)
bonne inconnue W:=d(0,4)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,5},2} qui est  maintenant AA:= - d(2,4)$

Unknown: d(2,4)
Unknown: d(2,4)
bonne inconnue W:=d(2,4)$

sa valeur doit etre WW:=0$

on resout l'equation {{0,5},4} qui est  maintenant AA:= - d(4,4) + d(2,2) + d(1,
3) + 2*d(0,0)$

Unknowns: {d(4,4),d(2,2),d(1,3),d(0,0)}
Unknowns: {d(4,4),d(2,2),d(1,3),d(0,0)}
bonne inconnue W:=d(1,3)$

sa valeur doit etre WW:=d(4,4) - d(2,2) - 2*d(0,0)$

on resout l'equation {{0,6},4} qui est  maintenant AA:=d(5,6) - d(4,5)$

Unknowns: {d(5,6),d(4,5)}
Unknowns: {d(5,6),d(4,5)}
bonne inconnue W:=d(5,6)$

sa valeur doit etre WW:=d(4,5)$

on resout l'equation {{0,6},5} qui est  maintenant AA:= - d(4,4) + d(2,6) + d(1,
1) + 3*d(0,0)$

Unknowns: {d(4,4),d(2,6),d(1,1),d(0,0)}
Unknowns: {d(4,4),d(2,6),d(1,1),d(0,0)}
bonne inconnue W:=d(4,4)$

sa valeur doit etre WW:=d(2,6) + d(1,1) + 3*d(0,0)$

on resout l'equation {{1,2},4} qui est  maintenant AA:= - d(2,6) + d(2,2) - 3*d(
0,0)$

Unknowns: {d(2,6),d(2,2),d(0,0)}
Unknowns: {d(2,6),d(2,2),d(0,0)}
bonne inconnue W:=d(2,6)$

sa valeur doit etre WW:=d(2,2) - 3*d(0,0)$

on resout l'equation {{1,2},5} qui est  maintenant AA:=d(0,1)$

Unknown: d(0,1)
Unknown: d(0,1)
bonne inconnue W:=d(0,1)$

sa valeur doit etre WW:=0$

on resout l'equation {{1,3},4} qui est  maintenant AA:= - d(4,5) + d(2,3)$

Unknowns: {d(4,5),d(2,3)}
Unknowns: {d(4,5),d(2,3)}
bonne inconnue W:=d(4,5)$

sa valeur doit etre WW:=d(2,3)$

on resout l'equation {{1,3},6} qui est  maintenant AA:= - d(0,3)$

Unknown: d(0,3)
Unknown: d(0,3)
bonne inconnue W:=d(0,3)$

sa valeur doit etre WW:=0$

on resout l'equation {{1,6},4} qui est  maintenant AA:=d(2,2) - 3*d(0,0)$

Unknowns: {d(2,2),d(0,0)}
Unknowns: {d(2,2),d(0,0)}
bonne inconnue W:=d(2,2)$

sa valeur doit etre WW:=3*d(0,0)$

on resout l'equation {{2,3},4} qui est  maintenant AA:= - d(1,1) + 2*d(0,0)$

Unknowns: {d(1,1),d(0,0)}
Unknowns: {d(1,1),d(0,0)}
bonne inconnue W:=d(1,1)$

sa valeur doit etre WW:=2*d(0,0)$

Derivation equations to cancel (Reduce output) : \\{{{{0,1},0},0},
{{{0,1},1},0},
{{{0,1},2},0},
{{{0,1},3},0},
{{{0,1},4},0},
{{{0,1},5},0},
{{{0,1},6},0},
{{{0,2},0},0},
{{{0,2},1},0},
{{{0,2},2},0},
{{{0,2},3},0},
{{{0,2},4},0},
{{{0,2},5},0},
{{{0,2},6},0},
{{{0,3},0},0},
{{{0,3},1},0},
{{{0,3},2},0},
{{{0,3},3},0},
{{{0,3},4},0},
{{{0,3},5},0},
{{{0,3},6},0},
{{{0,4},2},0},
{{{0,4},4},0},
{{{0,4},5},0},
{{{0,4},6},0},
{{{0,5},0},0},
{{{0,5},1},0},
{{{0,5},2},0},
{{{0,5},3},0},
{{{0,5},4},0},
{{{0,5},5},0},
{{{0,5},6},0},
{{{0,6},0},0},
{{{0,6},1},0},
{{{0,6},2},0},
{{{0,6},3},0},
{{{0,6},4},0},
{{{0,6},5},0},
{{{0,6},6},0},
{{{1,2},0},0},
{{{1,2},1},0},
{{{1,2},2},0},
{{{1,2},3},0},
{{{1,2},4},0},
{{{1,2},5},0},
{{{1,2},6},0},
{{{1,3},0},0},
{{{1,3},1},0},
{{{1,3},2},0},
{{{1,3},3},0},
{{{1,3},4},0},
{{{1,3},5},0},
{{{1,3},6},0},
{{{1,4},4},0},
{{{1,4},5},0},
{{{1,4},6},0},
{{{1,5},4},0},
{{{1,5},5},0},
{{{1,5},6},0},
{{{1,6},4},0},
{{{1,6},5},0},
{{{1,6},6},0},
{{{2,3},2},0},
{{{2,3},4},0},
{{{2,3},5},0},
{{{2,4},4},0},
{{{2,4},5},0},
{{{2,5},4},0},
{{{2,5},5},0},
{{{2,6},4},0},
{{{2,6},5},0},
{{{3,4},2},0},
{{{3,4},5},0},
{{{3,5},2},0},
{{{3,5},4},0},
{{{3,5},5},0},
{{{3,6},2},0},
{{{3,6},5},0},
{{{4,5},4},0},
{{{4,6},5},0},
{{{5,6},4},0},
{{{5,6},5},0}}$

Il n'y a pas de phase 2$

derivation generique de gtildedelta:$

MATD:=
mat((d(0,0),0,0,0,0,0,0),(d(1,0),2*d(0,0),0,0,0,0,0),(d(2,0),d(2,1),3*d(0,0),d(2
,3),0,0,0),(d(3,0),0,0,2*d(0,0),0,0,0),(d(4,0),d(4,1),d(4,2),d(4,3),5*d(0,0),d(2
,3),d(4,6)),(d(5,0),d(4,6) + d(2,0),d(2,3) - d(1,0),d(4,2),0,4*d(0,0),d(2,3)),(d
(6,0),d(3,0) + d(2,3) - d(2,1),0, - 2*d(1,0),0,0,3*d(0,0)))$

pour delta:=

[0  0  0  0  0  0]
[                ]
[0  0  1  0  0  0]
[                ]
[0  0  0  0  0  0]
[                ]
[0  0  0  0  1  0]
[                ]
[0  1  0  0  0  1]
[                ]
[1  0  0  0  0  0]


pour shortformdelta:={0,0,1,ss,1,0,ss,0,0,0,ss,0,1}

Unknowns: {d(6,0),
d(5,0),
d(4,6),
d(4,3),
d(4,2),
d(4,1),
d(4,0),
d(3,0),
d(2,3),
d(2,1),
d(2,0),
d(1,0),
d(0,0)}
Unknowns: {d(6,0),
d(5,0),
d(4,6),
d(4,3),
d(4,2),
d(4,1),
d(4,0),
d(3,0),
d(2,3),
d(2,1),
d(2,0),
d(1,0),
d(0,0)}
listeparametresMATD{d(6,0),
d(5,0),
d(4,6),
d(4,3),
d(4,2),
d(4,1),
d(4,0),
d(3,0),
d(2,3),
d(2,1),
d(2,0),
d(1,0),
d(0,0)}$

dim Der(gtildedelta):=13$

t1:=D(0,0):=

[1  0  0  0  0  0  0]
[                   ]
[0  2  0  0  0  0  0]
[                   ]
[0  0  3  0  0  0  0]
[                   ]
[0  0  0  2  0  0  0]
[                   ]
[0  0  0  0  5  0  0]
[                   ]
[0  0  0  0  0  4  0]
[                   ]
[0  0  0  0  0  0  3]


Unknown: d(0,0)

Unknown: d(0,0)

commutant de t1 dans der(gtildedelta):

[d(0,0)     0         0         0         0         0         0    ]
[                                                                  ]
[  0     2*d(0,0)     0         0         0         0         0    ]
[                                                                  ]
[  0        0      3*d(0,0)     0         0         0         0    ]
[                                                                  ]
[  0        0         0      2*d(0,0)     0         0         0    ]
[                                                                  ]
[  0        0         0         0      5*d(0,0)     0         0    ]
[                                                                  ]
[  0        0         0         0         0      4*d(0,0)     0    ]
[                                                                  ]
[  0        0         0         0         0         0      3*d(0,0)]


rank 1 with maximal torus t1

1


matrice de passage de la base X(0)=delta, X(1),..., X(6) a une base  diagonali\
sant le tore maximal: on peut prendre

P:=

[1  0  0  0  0  0  0]
[                   ]
[0  1  0  0  0  0  0]
[                   ]
[0  0  1  0  0  0  0]
[                   ]
[0  0  0  1  0  0  0]
[                   ]
[0  0  0  0  1  0  0]
[                   ]
[0  0  0  0  0  1  0]
[                   ]
[0  0  0  0  0  0  1]


P**(-1)*t1*P:=

[1  0  0  0  0  0  0]
[                   ]
[0  2  0  0  0  0  0]
[                   ]
[0  0  3  0  0  0  0]
[                   ]
[0  0  0  2  0  0  0]
[                   ]
[0  0  0  0  5  0  0]
[                   ]
[0  0  0  0  0  4  0]
[                   ]
[0  0  0  0  0  0  3]


matrice des derivations dans cette base diagonalisante Y(1),...,Y(7):

P**(-1)*MATD*P:=
mat((d(0,0),0,0,0,0,0,0),(d(1,0),2*d(0,0),0,0,0,0,0),(d(2,0),d(2,1),3*d(0,0),d(2
,3),0,0,0),(d(3,0),0,0,2*d(0,0),0,0,0),(d(4,0),d(4,1),d(4,2),d(4,3),5*d(0,0),d(2
,3),d(4,6)),(d(5,0),d(4,6) + d(2,0),d(2,3) - d(1,0),d(4,2),0,4*d(0,0),d(2,3)),(d
(6,0),d(3,0) + d(2,3) - d(2,1),0, - 2*d(1,0),0,0,3*d(0,0)))$

PP:=

[1  0  0  0  0  0  0]
[                   ]
[0  1  0  0  0  0  0]
[                   ]
[0  0  1  0  0  0  0]
[                   ]
[0  0  0  1  0  0  0]
[                   ]
[0  0  0  0  1  0  0]
[                   ]
[0  0  0  0  0  1  0]
[                   ]
[0  0  0  0  0  0  1]


avec PP:=P*Q:=

[1  0  0  0  0  0  0]
[                   ]
[0  1  0  0  0  0  0]
[                   ]
[0  0  1  0  0  0  0]
[                   ]
[0  0  0  1  0  0  0]
[                   ]
[0  0  0  0  1  0  0]
[                   ]
[0  0  0  0  0  1  0]
[                   ]
[0  0  0  0  0  0  1]


MATDDIAGONALISE:=

mat((d(0,0),0,0,0,0,0,0),

    (d(1,0),2*d(0,0),0,0,0,0,0),

    (d(2,0),d(2,1),3*d(0,0),d(2,3),0,0,0),

    (d(3,0),0,0,2*d(0,0),0,0,0),

    (d(4,0),d(4,1),d(4,2),d(4,3),5*d(0,0),d(2,3),d(4,6)),

    (d(5,0),d(4,6) + d(2,0),d(2,3) - d(1,0),d(4,2),0,4*d(0,0),d(2,3)),

    (d(6,0),d(3,0) + d(2,3) - d(2,1),0, - 2*d(1,0),0,0,3*d(0,0)))


on voit apparaitre les poids sur la diagonale

r(1) := d(0,0)

r(2) := 2*d(0,0)

r(3) := 3*d(0,0)

r(4) := 2*d(0,0)

r(5) := 5*d(0,0)

r(6) := 4*d(0,0)

r(7) := 3*d(0,0)

r(1) := gamma1

r(2) := 2*gamma1

r(3) := 3*gamma1

r(4) := 2*gamma1

r(5) := 5*gamma1

r(6) := 4*gamma1

r(7) := 3*gamma1

Le systeme de poids est le systeme 1.3

calcul de relations de commutation de la base diaY(j) diagonalisant le tore

listcommutateursdesx := {{{0,1},x(6)},

   {{0,2},x(5)},

   {{0,3},x(2)},

   {{0,4},0},

   {{0,5},x(4)},

   {{0,6},x(5)},

   {{1,2},x(4)},

   {{1,3},x(5)},

   {{1,4},0},

   {{1,5},0},

   {{1,6},0},

   {{2,3},0},

   {{2,4},0},

   {{2,5},0},

   {{2,6},0},

   {{3,4},0},

   {{3,5},0},

   {{3,6},0},

   {{4,5},0},

   {{4,6},0},

   {{5,6},0}}

diaY(1):=x(0)

diaY(2):=x(1)

diaY(3):=x(2)

diaY(4):=x(3)

diaY(5):=x(4)

diaY(6):=x(5)

diaY(7):=x(6)

liste des commutateurs des diaY(i) :$

listcommutateurdesdiaY:={{{1,2},diay(7)},
{{1,3},diay(6)},
{{1,4},diay(3)},
{{1,5},0},
{{1,6},diay(5)},
{{1,7},diay(6)},
{{2,3},diay(5)},
{{2,4},diay(6)},
{{2,5},0},
{{2,6},0},
{{2,7},0},
{{3,4},0},
{{3,5},0},
{{3,6},0},
{{3,7},0},
{{4,5},0},
{{4,6},0},
{{4,7},0},
{{5,6},0},
{{5,7},0},
{{6,7},0}}$

Now we make explicit the isomorphism with an algebra of the book:$

Namely g_{7,1.3}$

(iL)$

i.e. we go from the basis diaY(i) to the new basis ZZ(i) defined by the matrix:$

on pose :$

avec comme matrice de changement de base :$

mat((1,0,0,0,0,0,0),(0,-1,-1,0,0,0,0),(0,0,0,0,1,0,0),(0,0,1,0,0,0,0),(0,0,0,0,0
,0,-1),(0,0,0,0,0,-1,0),(0,0,0,-1,-1,0,0))$

det(isom):= -1$

ZZ(1):=diay(1)$

ZZ(2):= - diay(2)$

ZZ(3):=diay(4) - diay(2)$

ZZ(4):= - diay(7)$

ZZ(5):= - (diay(7) - diay(3))$

ZZ(6):= - diay(6)$

ZZ(7):= - diay(5)$

listcommutateursdesZZ:=$

{{1,2},zz(4)}$

{{1,3},zz(5)}$

{{1,4},zz(6)}$

{{1,5},0}$

{{1,6},zz(7)}$

{{1,7},0}$

{{2,3},zz(6)}$

{{2,4},0}$

{{2,5},zz(7)}$

{{2,6},0}$

{{2,7},0}$

{{3,4},0}$

{{3,5},zz(7)}$

{{3,6},0}$

{{3,7},0}$

{{4,5},0}$

{{4,6},0}$

{{4,7},0}$

{{5,6},0}$

{{5,7},0}$

{{6,7},0}$

We get the commutation relations of$

g_{7,1.3}$

(iL)$

with L:=0$

Et cela pour a:=1, b:=1.$

shortformdelta:={0,0,1,ss,1,0,ss,0,0,0,ss,0,1}$

delta:=
mat((0,0,0,0,0,0),(0,0,1,0,0,0),(0,0,0,0,0,0),(0,0,0,0,1,0),(0,1,0,0,0,1),(1,0,0
,0,0,0))$